The fundamental period of the function `f(x)=4cos^4((x-pi)/(4pi^2))-2cos((x-pi)/(2pi^2))` is equal to :

Explanation

To find the fundamental period of the function \( f(x) = 4 \cos^4\left(\frac{x - \pi}{4\pi^2}\right) - 2 \cos\left(\frac{x - \pi}{2\pi^2}\right) \), we will analyze each component of the function separately.

### Step 1: Identify the periods of the cosine functions

The function consists of two parts:
1. \( 4 \cos^4\left(\frac{x - \pi}{4\pi^2}\right) \)
2. \( -2 \cos\left(\frac{x - \pi}{2\pi^2}\right) \)

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