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Draw a rough sketch of the curve y=(x^2+...

Draw a rough sketch of the curve `y=(x^2+3x+2)/(x^2-3x+2)` and find the area of the bounded region between the curve and the x-axis.

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To solve the problem of finding the area of the bounded region between the curve \( y = \frac{x^2 + 3x + 2}{x^2 - 3x + 2} \) and the x-axis, we will follow these steps: ### Step 1: Factor the numerator and denominator First, we will factor the numerator and denominator of the function. - The numerator \( x^2 + 3x + 2 \) can be factored as: \[ x^2 + 3x + 2 = (x + 1)(x + 2) ...
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