A triangle ABC vertices A(5,1),B(-1,-7) and C(1,4). Respectively. L be the line mirror passing through C and parallel to AB. A light ray emanating from point A goes along the direction of the internal bisector of angle A, which meets the mirror and BC at E and D, respectively. then the sum of the areas of `Delta ACE and Delta ABC` is
A
17 sq. units
B
18 sq. units
C
`(50)/(3)` sq. units
D
20 sq. units
Text Solution
Verified by Experts
The correct Answer is:
C
`(AD)/(DE) =(BD)/(DC) =(AB)/(AC)` `:.` Point `D ((1)/(3),(1)/(3))` and `E(-2,0)`. Area of `DeltaADC +` Area of `DeltaBDE` `=(25)/(3) +(25)/(3)` `=(50)/(3)` sq. units
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CENGAGE ENGLISH-COORDINATE SYSTEM-Multiple Correct Answers Type
