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In the xy-plane, how many straight lines...

In the xy-plane, how many straight lines whose x-intercept is a prime number and whose y-intercept is a positive integer pass through the point (4,3)?

A

1

B

2

C

3

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find how many straight lines can be formed that pass through the point (4, 3), have an x-intercept that is a prime number, and a y-intercept that is a positive integer. ### Step-by-Step Solution: 1. **Write the equation of the line in intercept form:** The intercept form of the equation of a line is given by: \[ \frac{x}{p} + \frac{y}{q} = 1 \] where \( p \) is the x-intercept and \( q \) is the y-intercept. 2. **Substituting the point (4, 3) into the equation:** Since the line passes through the point (4, 3), we substitute \( x = 4 \) and \( y = 3 \) into the equation: \[ \frac{4}{p} + \frac{3}{q} = 1 \] 3. **Rearranging the equation:** Rearranging the equation gives: \[ \frac{4}{p} = 1 - \frac{3}{q} \] This can be rewritten as: \[ \frac{3}{q} = 1 - \frac{4}{p} \] 4. **Finding a common denominator:** We can express the right side with a common denominator: \[ \frac{3}{q} = \frac{p - 4}{p} \] 5. **Cross-multiplying:** Cross-multiplying gives us: \[ 3p = q(p - 4) \] Rearranging this, we find: \[ q = \frac{3p}{p - 4} \] 6. **Identifying conditions for \( q \):** Since \( q \) must be a positive integer, \( p - 4 \) must divide \( 3p \). This means \( p - 4 \) must be a divisor of \( 12 \) (since \( 3p \) can be expressed as \( 3(p - 4) + 12 \)). 7. **Finding divisors of 12:** The positive divisors of 12 are \( 1, 2, 3, 4, 6, 12 \). Therefore, we can set: \[ p - 4 = d \quad \text{where } d \text{ is a divisor of } 12 \] Hence, \( p = d + 4 \). 8. **Calculating possible values of \( p \):** - If \( d = 1 \), then \( p = 5 \) - If \( d = 2 \), then \( p = 6 \) (not prime) - If \( d = 3 \), then \( p = 7 \) - If \( d = 4 \), then \( p = 8 \) (not prime) - If \( d = 6 \), then \( p = 10 \) (not prime) - If \( d = 12 \), then \( p = 16 \) (not prime) 9. **Identifying prime numbers:** The only prime numbers obtained from the above calculations are \( p = 5 \) and \( p = 7 \). 10. **Conclusion:** Therefore, there are **two** straight lines that satisfy the conditions of the problem. ### Final Answer: The number of straight lines is **2**.

To solve the problem, we need to find how many straight lines can be formed that pass through the point (4, 3), have an x-intercept that is a prime number, and a y-intercept that is a positive integer. ### Step-by-Step Solution: 1. **Write the equation of the line in intercept form:** The intercept form of the equation of a line is given by: \[ \frac{x}{p} + \frac{y}{q} = 1 ...
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