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The base B C of a A B C is bisected at ...

The base `B C` of a ` A B C` is bisected at the point `(p ,q)` & the equation to the side `A B&A C` are `p x+q y=1` & `q x+p y=1` . The equation of the median through `A` is: `(p-2q)x+(q-2p)y+1=0` `(p+q)(x+y)-2=0` `(2p q-1)(p x+q y-1)=(p^2+q^2-1)(q x+p y-1)` none of these

A

`qx - py = 0`

B

`(x)/(p) +(y)/(q) = 2`

C

`(2pq -1) (px +qy-1) =(p^(2)+q^(2)-1) (qx+py-1)`

D

`(p-2q)x+(q-2p)y = p^(2) +r^(2)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the equation of the median through point A in triangle ABC, given that the base BC is bisected at point (p, q) and the equations of sides AB and AC are provided. ### Step-by-Step Solution: 1. **Understanding the Given Information:** - The base BC is bisected at point (p, q). - The equations of sides AB and AC are: - \( px + qy = 1 \) (Equation of line AB) - \( qx + py = 1 \) (Equation of line AC) 2. **Finding the Equation of the Median:** - The median from vertex A to the midpoint of BC (which is (p, q)) can be derived using the concept of linear combinations of the equations of lines AB and AC. - The general form for the equation of the median can be expressed as: \[ L_1 + \lambda L_2 = 0 \] where \( L_1 \) and \( L_2 \) are the equations of lines AB and AC respectively. 3. **Setting Up the Equation:** - We can write: \[ px + qy - 1 + \lambda (qx + py - 1) = 0 \] - Rearranging gives: \[ (p + \lambda q)x + (q + \lambda p)y - (1 + \lambda) = 0 \] 4. **Substituting the Midpoint (p, q):** - Since the median passes through the point (p, q), we substitute \( x = p \) and \( y = q \) into the equation: \[ (p + \lambda q)p + (q + \lambda p)q - (1 + \lambda) = 0 \] - This simplifies to: \[ p^2 + \lambda pq + q^2 + \lambda pq - (1 + \lambda) = 0 \] - Combining like terms gives: \[ p^2 + q^2 + 2\lambda pq - (1 + \lambda) = 0 \] 5. **Solving for λ:** - Rearranging gives: \[ 2\lambda pq - \lambda = 1 - (p^2 + q^2) \] - Factoring out λ: \[ \lambda(2pq - 1) = 1 - (p^2 + q^2) \] - Solving for λ: \[ \lambda = \frac{1 - (p^2 + q^2)}{2pq - 1} \] 6. **Substituting λ back into the Median Equation:** - Now substitute λ back into the median equation: \[ (p + \frac{1 - (p^2 + q^2)}{2pq - 1} q)x + (q + \frac{1 - (p^2 + q^2)}{2pq - 1} p)y - (1 + \frac{1 - (p^2 + q^2)}{2pq - 1}) = 0 \] - After simplification, we arrive at the final equation of the median. 7. **Identifying the Correct Option:** - After simplifying the median equation, we can compare it with the provided options: - The correct option is: \[ (2pq - 1)(px + qy - 1) = (p^2 + q^2 - 1)(qx + py - 1) \] ### Final Answer: The equation of the median through A is: \[ (2pq - 1)(px + qy - 1) = (p^2 + q^2 - 1)(qx + py - 1) \]

To solve the problem, we need to find the equation of the median through point A in triangle ABC, given that the base BC is bisected at point (p, q) and the equations of sides AB and AC are provided. ### Step-by-Step Solution: 1. **Understanding the Given Information:** - The base BC is bisected at point (p, q). - The equations of sides AB and AC are: - \( px + qy = 1 \) (Equation of line AB) ...
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