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Find the length of intercept, the circle...

Find the length of intercept, the circle `x^2+y^2+10 x-6y+9=0` makes on the x-axis.

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To find the length of the intercept that the circle \(x^2 + y^2 + 10x - 6y + 9 = 0\) makes on the x-axis, we will follow these steps: ### Step 1: Rewrite the equation of the circle in standard form The given equation of the circle is: \[ x^2 + y^2 + 10x - 6y + 9 = 0 \] We can rearrange this equation to group the \(x\) and \(y\) terms: ...
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