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Tangents P Aa n dP B are drawn to x^2+y^...

Tangents `P Aa n dP B` are drawn to `x^2+y^2=a^2` from the point `P(x_1, y_1)dot` Then find the equation of the circumcircle of triangle `P A Bdot`

Text Solution

Verified by Experts


From the figure, clearly the points O,A,P and B are concyclic and OP is diameter of the circle.
Thus, equation of circumcircle of triangle PAB is
`x(x-x_(1))+y(y-y_(1))=0`
or `x^(2)+y^(2)-x x_(1)-y y_(1)=0`
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