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Find the greatest distance of the point `P(10 ,7)` from the circle `x^2+y^2-4x-2y-20=0`

Text Solution

Verified by Experts

Center of the given circle is C(2,1) and radius is `r=sqrt((-2)^(2)+(-1)^(2)-(-20))=5`.
Now, `PC=sqrt((10-2)^(2)+(7-1)^(2))=10`
Therefore,
Greatest distance of point P from circle`=PC+r=10+5=15`
Least distance of point P from circle `=|PC-r|=|10-5|=5`
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