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Find the equation of chord of the circle...

Find the equation of chord of the circle `x^(2)+y^(2)-2x-4y-4=0` passing through the point (2,3) which has shortest length.

Text Solution

Verified by Experts

Clearly required chord of the circle is that one which is bisected at point (2,3) .
So, using `T=S_(1)` , equation of chord is
`2x+3y-(x+2)-2(y+3)-4=2^(2)+3^(2)-2(2)-4(3)-4` or `x+y-5=0`
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