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A chord of the circle x^2 + y^2 - 4x - 6...

A chord of the circle `x^2 + y^2 - 4x - 6y = 0` passing through the origin subtends an angle arctan(7/4) at the point where the circle meets positive y-axis. Equation of the chord is

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To solve the question step by step, we will follow the outlined process: ### Step 1: Rewrite the Circle's Equation The given equation of the circle is: \[ x^2 + y^2 - 4x - 6y = 0 \] We will rearrange it into the standard form of a circle. ### Step 2: Completing the Square ...
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