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Find the equation of the normals to the ...

Find the equation of the normals to the circle `x^2+y^2-8x-2y+12=0` at the point whose ordinate is `-1`

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To find the equation of the normals to the circle given by the equation \(x^2 + y^2 - 8x - 2y + 12 = 0\) at the point where the ordinate is \(-1\), we will follow these steps: ### Step 1: Rewrite the Circle Equation First, we rewrite the equation of the circle in standard form. The given equation is: \[ x^2 + y^2 - 8x - 2y + 12 = 0 \] We can rearrange it as: ...
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