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Find the values of k for which the point...

Find the values of `k` for which the points `(2k ,3k),(1,0),(0,1),a n d(0,0)` lie on a circle.

Text Solution

Verified by Experts

The correct Answer is:
`5//13`
The circle passing through (1,0),(0,1) and (0,0) is
`x(x-1)+y(y-1)=0`
It also passes through the point (2k,3k). Therefore,
`2k(2k-1)+3k(3k-1)=0`
i.e., `k=0` or `k=(5)/(13)`
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