In `triangleABC`, if `sqrt(3)sin C=2 sec A-tan A`, then prove that triangle is right angled.

Explanation

To prove that triangle ABC is a right-angled triangle given the equation \(\sqrt{3} \sin C = 2 \sec A - \tan A\), we will follow these steps:

### Step 1: Rewrite the equation using trigonometric identities
We start with the given equation:
\[ \sqrt{3} \sin C = 2 \sec A - \tan A \]
Using the identities \(\sec A = \frac{1}{\cos A}\) and \(\tan A = \frac{\sin A}{\cos A}\), we can rewrite the right side:
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