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Prove that sin6^0sin42^0sin66^0sin78^0=1...

Prove that `sin6^0sin42^0sin66^0sin78^0=1/(16)`

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To prove that \( \sin 6^\circ \sin 42^\circ \sin 66^\circ \sin 78^\circ = \frac{1}{16} \), we can use trigonometric identities to simplify the expression step by step. ### Step-by-Step Solution: 1. **Start with the Left-Hand Side (LHS)**: \[ LHS = \sin 6^\circ \sin 42^\circ \sin 66^\circ \sin 78^\circ \] ...
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