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Prove that sintheta+s in3theta+sin5theta...

Prove that `sintheta+s in3theta+sin5theta++sin(2n-1)theta=(sin^2ntheta)/(sintheta)dot`

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To prove the equation \[ \sin \theta + \sin 3\theta + \sin 5\theta + \ldots + \sin(2n-1)\theta = \frac{\sin^2 n\theta}{\sin \theta} \] we will follow these steps: ...
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