If `x^2+y x^2=4` then find the xamimum value of `(x^3+y^3)/(x+y)`

Explanation

To find the maximum value of \(\frac{x^3 + y^3}{x + y}\) given that \(x^2 + y^2 = 4\), we can follow these steps:

### Step 1: Rewrite the expression
We start with the expression we want to maximize:
\[ \frac{x^3 + y^3}{x + y} \]
Using the identity \(x^3 + y^3 = (x + y)(x^2 - xy + y^2)\), we can rewrite our expression as:
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