If `(1-tan theta)(1+tan theta)sec^2 theta+2^(tan^2 theta)=0` then in the interval `(-pi/2,pi/2),` the value of `theta` is

Explanation

To solve the equation \( (1 - \tan \theta)(1 + \tan \theta) \sec^2 \theta + 2^{\tan^2 \theta} = 0 \), we can follow these steps:

### Step 1: Rewrite the equation
The given equation can be rewritten using the identity \( \sec^2 \theta = 1 + \tan^2 \theta \):
\[ (1 - \tan \theta)(1 + \tan \theta)(1 + \tan^2 \theta) + 2^{\tan^2 \theta} = 0 \]

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