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Solve sec 4 theta- sec 2 theta=2....

Solve sec `4 theta- sec 2 theta=2`.

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`1/(cos 4 theta)-1/(cos 2 theta)=2`
or `cos 2 theta-cos 4 theta =2 cos 2 theta cos 4 theta = cos 2 theta + cos 6 theta`
or `cos 6 theta + cos 4 theta=0`
or `2 cos 5 theta cos theta =0`
`rArr cos 5 theta=0" "or cos theta =0`
`rArr 5 theta=(2n+1) pi/2 or theta=(2n+1) pi/2, n in Z`
`rArr theta=(n+1/2) pi/5 or theta=(n+1/2) pi, n in Z`
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