Solve `(sin^(2) 2x+4 sin^(4) x-4 sin^(2) x cos^(2) x)/(4-sin^(2) 2x-4 sin^(2) x)=1/9`.

Explanation

To solve the equation

\[ \frac{\sin^2 2x + 4 \sin^4 x - 4 \sin^2 x \cos^2 x}{4 - \sin^2 2x - 4 \sin^2 x} = \frac{1}{9}, \]

we will follow these steps:

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