Find the number of solution of `sin^2xcos^2x=1+cos^2xsin^4x` in the interval `[0,2pi]dot`

Explanation

To solve the equation \( \sin^2 x \cos^2 x = 1 + \cos^2 x \sin^4 x \) in the interval \([0, 2\pi]\), we will follow these steps:

### Step 1: Rearranging the Equation
We start by moving all terms to one side of the equation:
\[ \sin^2 x \cos^2 x - \cos^2 x \sin^4 x - 1 = 0 \]

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