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Given that log(2)3=a,log(3)5=b,log(7)2=c...

Given that `log_(2)3=a,log_(3)5=b,log_(7)2=c`, express the logaithm of the number 63 to the base 140 in terms of a,b and c.

A

`(2+ac)/(2c+1+abc)`

B

`(1+2ac)/(c+2+abc)`

C

`(1+2ac)/(2c+1+abc)`

D

`(2+ac)/(c+2+abc)`

Text Solution

Verified by Experts

The correct Answer is:
C

`log_(140)63=(log_(7)7+2log_(7)3)/(2log_(7)2+log_(7)7+log_(7)5)`
`=(1+2ac)/(2c+1+abc)`
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