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The number of integral solutions of log(...

The number of integral solutions of `log_(9)(x+1).log_(2)(x+1)-log_(9)(x+1)-log_(2)(x+1)+1lt0` is

A

4

B

5

C

6

D

7

Text Solution

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The correct Answer is:
To solve the inequality \( \log_{9}(x+1) \cdot \log_{2}(x+1) - \log_{9}(x+1) - \log_{2}(x+1) + 1 < 0 \), we will follow these steps: ### Step 1: Rewrite the Inequality We start with the given inequality: \[ \log_{9}(x+1) \cdot \log_{2}(x+1) - \log_{9}(x+1) - \log_{2}(x+1) + 1 < 0 \] We can rearrange it as: \[ \log_{9}(x+1) \cdot \log_{2}(x+1) - \log_{9}(x+1) - \log_{2}(x+1) < -1 \] ### Step 2: Factor the Left Side Next, we factor the left-hand side: \[ (\log_{9}(x+1) - 1)(\log_{2}(x+1) - 1) < 0 \] This means we need to analyze the product of two terms. ### Step 3: Set Each Term to Zero Now, we find the points where each term is zero: 1. \( \log_{9}(x+1) - 1 = 0 \) implies \( \log_{9}(x+1) = 1 \) which gives \( x + 1 = 9 \) or \( x = 8 \). 2. \( \log_{2}(x+1) - 1 = 0 \) implies \( \log_{2}(x+1) = 1 \) which gives \( x + 1 = 2 \) or \( x = 1 \). ### Step 4: Analyze Intervals Now we analyze the intervals determined by the roots \( x = 1 \) and \( x = 8 \): - Interval 1: \( (-\infty, 1) \) - Interval 2: \( (1, 8) \) - Interval 3: \( (8, \infty) \) ### Step 5: Test Each Interval We will test a point in each interval to see where the product is negative: 1. **For \( x < 1 \)** (e.g., \( x = 0 \)): - \( \log_{9}(1) - 1 = -1 \) (negative) - \( \log_{2}(1) - 1 = -1 \) (negative) - Product: Positive 2. **For \( 1 < x < 8 \)** (e.g., \( x = 2 \)): - \( \log_{9}(3) - 1 < 0 \) (negative) - \( \log_{2}(3) - 1 > 0 \) (positive) - Product: Negative 3. **For \( x > 8 \)** (e.g., \( x = 9 \)): - \( \log_{9}(10) - 1 > 0 \) (positive) - \( \log_{2}(10) - 1 > 0 \) (positive) - Product: Positive ### Step 6: Determine the Solution Set The inequality \( (\log_{9}(x+1) - 1)(\log_{2}(x+1) - 1) < 0 \) holds true in the interval \( (1, 8) \). ### Step 7: Find Integral Solutions The integral solutions in the interval \( (1, 8) \) are: \[ x = 2, 3, 4, 5, 6, 7 \] Thus, there are a total of 6 integral solutions. ### Final Answer The number of integral solutions is \( \boxed{6} \).

To solve the inequality \( \log_{9}(x+1) \cdot \log_{2}(x+1) - \log_{9}(x+1) - \log_{2}(x+1) + 1 < 0 \), we will follow these steps: ### Step 1: Rewrite the Inequality We start with the given inequality: \[ \log_{9}(x+1) \cdot \log_{2}(x+1) - \log_{9}(x+1) - \log_{2}(x+1) + 1 < 0 \] We can rearrange it as: ...
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