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Find the solution of the inequality 2log...

Find the solution of the inequality `2log_(1/4)(x+5)>9/4log_(1/(3sqrt(3)))(9)+log_(sqrt(x+5))(2)`

A

`(-5,-4)`

B

`(-3,-1)`

C

`(-4,-1)`

D

`(-5,-2)`

Text Solution

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The correct Answer is:
To solve the inequality \( 2\log_{1/4}(x+5) > \frac{9}{4}\log_{1/(3\sqrt{3})}(9) + \log_{\sqrt{x+5}}(2) \), we will follow these steps: ### Step 1: Simplify the logarithmic terms We start by simplifying each logarithmic term in the inequality. 1. **First term**: \[ 2\log_{1/4}(x+5) = 2\log_{2^{-2}}(x+5) = 2 \cdot \frac{-\log_2(x+5)}{-2} = -\log_2(x+5) \] 2. **Second term**: \[ \frac{9}{4}\log_{1/(3\sqrt{3})}(9) = \frac{9}{4} \cdot \frac{-\log_3(9)}{-\log_3(3\sqrt{3})} \] Since \(\log_3(9) = 2\) and \(\log_3(3\sqrt{3}) = 1 + \frac{1}{2} = \frac{3}{2}\), \[ = \frac{9}{4} \cdot \frac{-2}{-\frac{3}{2}} = \frac{9}{4} \cdot \frac{4}{3} = 3 \] 3. **Third term**: \[ \log_{\sqrt{x+5}}(2) = \frac{\log_2(2)}{\log_2(\sqrt{x+5})} = \frac{1}{\frac{1}{2}\log_2(x+5)} = \frac{2}{\log_2(x+5)} \] ### Step 2: Substitute back into the inequality Now we substitute the simplified terms back into the inequality: \[ -\log_2(x+5) > 3 + \frac{2}{\log_2(x+5)} \] ### Step 3: Let \( y = \log_2(x+5) \) Substituting \( y \) into the inequality gives: \[ -y > 3 + \frac{2}{y} \] Multiplying through by -1 (and reversing the inequality): \[ y < -3 - \frac{2}{y} \] ### Step 4: Multiply through by \( y \) (assuming \( y \neq 0 \)) \[ y^2 + 3y + 2 < 0 \] ### Step 5: Factor the quadratic Factoring gives: \[ (y + 1)(y + 2) < 0 \] ### Step 6: Determine the intervals The roots of the equation are \( y = -1 \) and \( y = -2 \). The quadratic opens upwards, so the solution to the inequality is: \[ -2 < y < -1 \] ### Step 7: Substitute back for \( y \) Substituting back for \( y \): \[ -2 < \log_2(x+5) < -1 \] ### Step 8: Convert back to exponential form This gives us: \[ 2^{-2} < x + 5 < 2^{-1} \] Which simplifies to: \[ \frac{1}{4} < x + 5 < \frac{1}{2} \] ### Step 9: Solve for \( x \) Subtracting 5 from all parts: \[ \frac{1}{4} - 5 < x < \frac{1}{2} - 5 \] This simplifies to: \[ -\frac{19}{4} < x < -\frac{9}{2} \] ### Final Answer Thus, the solution to the inequality is: \[ x \in \left(-\frac{19}{4}, -\frac{9}{2}\right) \]

To solve the inequality \( 2\log_{1/4}(x+5) > \frac{9}{4}\log_{1/(3\sqrt{3})}(9) + \log_{\sqrt{x+5}}(2) \), we will follow these steps: ### Step 1: Simplify the logarithmic terms We start by simplifying each logarithmic term in the inequality. 1. **First term**: \[ 2\log_{1/4}(x+5) = 2\log_{2^{-2}}(x+5) = 2 \cdot \frac{-\log_2(x+5)}{-2} = -\log_2(x+5) ...
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