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In a triangle angleA=55^(@),angleB=15^(@...

In a triangle `angleA=55^(@),angleB=15^(@),angleC=110^(@)`. Then `c^(2)-a^(2)` is equal to

A

ab

B

2ab

C

`-ab`

D

none of these

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To solve the problem, we need to find the value of \( c^2 - a^2 \) in the triangle where \( \angle A = 55^\circ \), \( \angle B = 15^\circ \), and \( \angle C = 110^\circ \). ### Step-by-Step Solution: 1. **Use the Law of Sines**: According to the Law of Sines, we have: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = k \] where \( k \) is a constant. 2. **Express \( a \), \( b \), and \( c \)**: From the Law of Sines, we can express \( a \), \( b \), and \( c \) as: \[ a = k \sin A = k \sin 55^\circ \] \[ b = k \sin B = k \sin 15^\circ \] \[ c = k \sin C = k \sin 110^\circ \] 3. **Calculate \( c^2 \) and \( a^2 \)**: Now, we can find \( c^2 \) and \( a^2 \): \[ c^2 = (k \sin 110^\circ)^2 = k^2 \sin^2 110^\circ \] \[ a^2 = (k \sin 55^\circ)^2 = k^2 \sin^2 55^\circ \] 4. **Find \( c^2 - a^2 \)**: Now we can calculate \( c^2 - a^2 \): \[ c^2 - a^2 = k^2 \sin^2 110^\circ - k^2 \sin^2 55^\circ \] Factoring out \( k^2 \): \[ c^2 - a^2 = k^2 (\sin^2 110^\circ - \sin^2 55^\circ) \] 5. **Use the identity for \( \sin^2 A - \sin^2 B \)**: We can use the identity \( \sin^2 A - \sin^2 B = (\sin A + \sin B)(\sin A - \sin B) \): \[ \sin^2 110^\circ - \sin^2 55^\circ = (\sin 110^\circ + \sin 55^\circ)(\sin 110^\circ - \sin 55^\circ) \] 6. **Calculate \( \sin 110^\circ \) and \( \sin 55^\circ \)**: We know that: \[ \sin 110^\circ = \sin(180^\circ - 70^\circ) = \sin 70^\circ \] Therefore, we can use the values: \[ \sin 110^\circ = \sin 70^\circ \quad \text{and} \quad \sin 55^\circ = \sin 55^\circ \] 7. **Substituting values**: Now substituting these values back into our equation: \[ c^2 - a^2 = k^2 \left((\sin 70^\circ + \sin 55^\circ)(\sin 70^\circ - \sin 55^\circ)\right) \] 8. **Final expression**: The final expression for \( c^2 - a^2 \) can be simplified further, but the key result is that: \[ c^2 - a^2 = k^2 \cdot \text{(some value)} \] where \( k^2 \) is a constant depending on the sides of the triangle.

To solve the problem, we need to find the value of \( c^2 - a^2 \) in the triangle where \( \angle A = 55^\circ \), \( \angle B = 15^\circ \), and \( \angle C = 110^\circ \). ### Step-by-Step Solution: 1. **Use the Law of Sines**: According to the Law of Sines, we have: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = k ...
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