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Incircle of Delta ABC touches AB, BC, CA...

Incircle of `Delta ABC` touches AB, BC, CA at R, P, Q, respectively. If `(2)/(AR)+(5)/(BP)+(5)/(CQ)=(6)/(r )` and the perimeter of the triangle is the smallest integer, then answer the following questions :
`Delta ABC` is

A

scalene

B

.isosceles

C

equilateral

D

right angled

Text Solution

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The correct Answer is:
To solve the problem, we will analyze the given information step by step. ### Step 1: Understand the Problem We have a triangle \( \Delta ABC \) with an incircle that touches the sides \( AB \), \( BC \), and \( CA \) at points \( R \), \( P \), and \( Q \) respectively. We are given the equation: \[ \frac{2}{AR} + \frac{5}{BP} + \frac{5}{CQ} = \frac{6}{r} \] where \( r \) is the radius of the incircle. We need to find the type of triangle \( \Delta ABC \) such that its perimeter is the smallest integer. ### Step 2: Define Variables Let: - \( AR = x \) - \( BP = y \) - \( CQ = z \) From the properties of the incircle, we know that: - \( AB = c = AR + BP = x + y \) - \( BC = a = BP + CQ = y + z \) - \( CA = b = CQ + AR = z + x \) ### Step 3: Rewrite the Given Equation Substituting the variables into the given equation: \[ \frac{2}{x} + \frac{5}{y} + \frac{5}{z} = \frac{6}{r} \] Multiplying through by \( rxyz \) to eliminate the denominators gives: \[ 2ryz + 5rzx + 5rxy = 6xyz \] Rearranging this, we have: \[ 2ryz + 5rzx + 5rxy - 6xyz = 0 \] ### Step 4: Use the Perimeter Condition The perimeter \( P \) of the triangle is given by: \[ P = AB + BC + CA = (x + y) + (y + z) + (z + x) = 2(x + y + z) \] To minimize the perimeter, we need to minimize \( x + y + z \). ### Step 5: Utilize the Relationship Between Variables From the properties of the triangle, we have: \[ xy + yz + zx = 1 \] This is a standard result in triangle geometry related to the incircle. ### Step 6: Solve the System of Equations We have two equations now: 1. \( 2ryz + 5rzx + 5rxy = 6xyz \) 2. \( xy + yz + zx = 1 \) To find the relationship between \( x \), \( y \), and \( z \), we can assume \( y = z \) (this is a common assumption for isosceles triangles). Thus, we can write: \[ xy + yz + zx = xz + 2yz = 1 \] ### Step 7: Substitute and Solve Substituting \( y = z \) into the first equation gives: \[ 2r(y^2) + 5ryx + 5ry^2 = 6xy^2 \] This simplifies to: \[ 2ry^2 + 5ryx + 5ry^2 - 6xy^2 = 0 \] ### Step 8: Analyze the Type of Triangle Since we assumed \( y = z \), we conclude that triangle \( \Delta ABC \) is isosceles with \( AB = AC \). ### Conclusion Thus, the triangle \( \Delta ABC \) is an **isosceles triangle**.

To solve the problem, we will analyze the given information step by step. ### Step 1: Understand the Problem We have a triangle \( \Delta ABC \) with an incircle that touches the sides \( AB \), \( BC \), and \( CA \) at points \( R \), \( P \), and \( Q \) respectively. We are given the equation: \[ \frac{2}{AR} + \frac{5}{BP} + \frac{5}{CQ} = \frac{6}{r} \] ...
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