Home
Class 12
MATHS
The vectors x hati + (x+1)hatj + (x+2)ha...

The vectors `x hati + (x+1)hatj + (x+2)hatk, (x+3)hati+ (x+4)hatj + (x+5)hatk and (x+6)hati + (x+7)hatj+ (x+8)hatk` are coplanar if x is equal to

A

1

B

-3

C

4

D

0

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

` x hati + (x + 1) hatj + (x +2) hatk , ( x+3) hati + (x +4) hatj + ( x+5) hatk and ( x+6) hati + (x+7) hatj+ ( x+8) hatk` are coplanar. We have determinant of their coefficients
as `|{:(x,,x+1,,x+2),(x+3,,x+4,,x+5),(x+6,,x+7,,x+8):}|`
Applying `C_2 to C_2 - C_1 and C_3 to C_3-C_1`, we have
`|{:(x,,1,,2),(x+3,,1,,2),(x+6,,1,,2):}|=0`
Here , `x in R`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • INTRODUCTION TO VECTORS

    CENGAGE ENGLISH|Exercise REASONING TYPE|11 Videos
  • INTRODUCTION TO VECTORS

    CENGAGE ENGLISH|Exercise LINKED COMPREHENSION TYPE|11 Videos
  • INTRODUCTION TO VECTORS

    CENGAGE ENGLISH|Exercise SINGLE CORRECT ANSWER TYPE|40 Videos
  • INTEGRALS

    CENGAGE ENGLISH|Exercise All Questions|764 Videos
  • INVERSE TRIGONOMETRIC FUNCTIONS

    CENGAGE ENGLISH|Exercise Archives (Numerical Value type)|2 Videos

Similar Questions

Explore conceptually related problems

The vectors veca=xhati+(x+1)hatj+(x+2)hatk , vecb=(x+3)hati+(x+4)hatj+(x+5)hatk and vecc=(x+6)hati+(x+7)hatj+(x+8)hatk are coplanar for

If three points A, B and C have position vectors hati + x hatj + 3 hatk, 3 hati + 4 hatj + 7 hatk and y hati -2hatj - 5 hatk respectively are collinear, then (x, y) =

The vectors lambdahati + hatj + 2hatk, hati + lambdahatj +hatk, 2hati - hatj + 2hatk are coplanar, if:

Find lambda if the vectors hati\ -\ hatj\ +\ hatk,\ 3 hati+\ hatj\ +\ 2 hatk\ and\ hati+lambda hatj+ hat3k\ are coplanar

If vectors veca =hati +2hatj -hatk, vecb = 2hati -hatj +hatk and vecc = lamdahati +hatj +2hatk are coplanar, then find the value of lamda .

If the vectors 4hati+11hatj+mhatk,7hati+2hatj+6hatk and hati+5hatj+4hatk are coplanar, then m is equal to

If the vectors (x^(2)-1)hati+2(x^(2)-1)hatj-3(x^(2)-1)hatk , (2x^(2)-1)hati+(2x^(2)+1)hatj+x^(2)hatk and (3x^(2)+2)hati+(x^(2)+4)hatj+(x^(2)+1)hatk are non - coplanar, then the number of real value x cannot take is

If the vectors veca = ( c log_(2) x ) hati - 6hatj + 3hatk and vecb=(log_(2)x )hati + 2hatj + (2clog_(2)x)hatk make an obtuse angle for any x = ( 0 , oo) then c belongs to

Let a=3hati + 2hatj + xhatk and b = hati - hatj + hatk , for some real x. Then |a+b| = r is possible if.

Show that the vectors 2hati-3hatj+4hatk and -4hati+6hatj-8hatk are collinear.