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If a^3+b^3+6a b c=8c^3 & omega is a cube...

If `a^3+b^3+6a b c=8c^3 & omega` is a cube root of unity then: (a)`a , b , c` are in `A.P.` (b) `a , b , c ,` are in `H.P.` (c) `a+bomega-2comega^2=0` (d) `a+bomega^2-2comega=0`

A

`a,c,b` are in A.P

B

a,c,b are in H.P

C

`a+bomega - 2comega^(2) = 0`

D

`a+ bomega^(2) -2comega = 0`

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To solve the problem, we start with the equation given: \[ a^3 + b^3 + 6abc = 8c^3 \] ### Step 1: Rearranging the Equation We can rearrange the equation as follows: \[ a^3 + b^3 - 8c^3 + 6abc = 0 \] ### Step 2: Using the Identity for Sums of Cubes We can apply the identity for the sum of cubes, which states that: \[ x^3 + y^3 + z^3 - 3xyz = (x+y+z)(x^2 + y^2 + z^2 - xy - xz - yz) \] In our case, let \( x = a \), \( y = b \), and \( z = -2c \). Thus, we can rewrite the equation: \[ a^3 + b^3 + (-2c)^3 - 3ab(-2c) = 0 \] This simplifies to: \[ a^3 + b^3 - 8c^3 + 6abc = 0 \] ### Step 3: Setting Up the Condition From the identity, we know that if \( a + b - 2c = 0 \), then: \[ a + b = 2c \] ### Step 4: Concluding that \( a, b, c \) are in Arithmetic Progression (A.P.) Since \( a + b = 2c \), we can conclude that \( a, b, c \) are in Arithmetic Progression (A.P.) because the average of \( a \) and \( b \) is \( c \). ### Step 5: Using the Properties of Cube Roots of Unity Next, we consider the cube root of unity, denoted as \( \omega \), where: \[ \omega^3 = 1 \quad \text{and} \quad 1 + \omega + \omega^2 = 0 \] ### Step 6: Applying the Cube Root of Unity Using the property of cube roots of unity, we can write: 1. For \( a + b\omega - 2c\omega^2 = 0 \) 2. For \( a + b\omega^2 - 2c\omega = 0 \) Both of these equations can be derived similarly to how we derived the A.P. condition. ### Final Conclusion From the above steps, we conclude: (a) \( a, b, c \) are in A.P. (Correct) (c) \( a + b\omega - 2c\omega^2 = 0 \) (Correct) (d) \( a + b\omega^2 - 2c\omega = 0 \) (Correct) ### Summary of Correct Options The correct options are: - (a) \( a, b, c \) are in A.P. - (c) \( a + b\omega - 2c\omega^2 = 0 \) - (d) \( a + b\omega^2 - 2c\omega = 0 \) ---

To solve the problem, we start with the equation given: \[ a^3 + b^3 + 6abc = 8c^3 \] ### Step 1: Rearranging the Equation We can rearrange the equation as follows: \[ a^3 + b^3 - 8c^3 + 6abc = 0 \] ...
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