If the sum of the n terms of a G.P. is `(3^(n)-1)`, then find the sum of the series whose terms are reciprocal of the given G.P..

Explanation

To solve the problem, we need to find the sum of the series whose terms are the reciprocals of the terms of a given geometric progression (G.P.) where the sum of the first n terms is given as \( S_n = 3^n - 1 \).

### Step 1: Find the nth term of the G.P.

The nth term \( T_n \) of a G.P. can be found using the formula:
\[ T_n = S_n - S_{n-1} \]
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