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If the sum of n , 2n , 3n terms of an AP...

If the sum of `n , 2n , 3n` terms of an AP are `S_1,S_2,S_3` respectively . Prove that `S_3=3(S_2-S_1)`

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To prove that \( S_3 = 3(S_2 - S_1) \) where \( S_1, S_2, \) and \( S_3 \) are the sums of \( n, 2n, \) and \( 3n \) terms of an arithmetic progression (AP), we will follow these steps: ### Step 1: Write the formula for the sum of the first \( n \) terms of an AP The sum of the first \( n \) terms of an AP is given by the formula: \[ S_n = \frac{n}{2} \left(2a + (n - 1)d\right) \] where \( a \) is the first term and \( d \) is the common difference. ...
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