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The ratio of the sum of ma n dn terms of...

The ratio of the sum of `ma n dn` terms of an A.P. is `m^2: n^2dot` Show that the ratio of the mth and nth terms is `(2m-1):(2n-1)dot`

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To show that the ratio of the mth and nth terms of an arithmetic progression (A.P.) is \((2m-1):(2n-1)\) given that the ratio of the sum of \(m\) and \(n\) terms of the A.P. is \(m^2:n^2\), we can follow these steps: ### Step 1: Define the terms of the A.P. Let \(a\) be the first term and \(d\) be the common difference of the A.P. The \(m\)th term \(T_m\) and \(n\)th term \(T_n\) can be expressed as: \[ T_m = a + (m-1)d \] \[ ...
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