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underset("n-digits")((666 . . . .6)^(2))...

`underset("n-digits")((666 . . . .6)^(2))+underset("n-digits")((888 . . . .8))` is equal to

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To solve the problem, we need to evaluate the expression: \[ \text{underset("n-digits")}\left((666\ldots6)^{2}\right) + \text{underset("n-digits")}\left((888\ldots8)\right) \] where \( (666\ldots6) \) has \( n \) digits and \( (888\ldots8) \) also has \( n \) digits. ...
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