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The value of 0. 2^(logsqrt(5)1/4+1/8+1/(...

The value of `0. 2^(logsqrt(5)1/4+1/8+1/(16)+)` is `4` b. `log4` c. `log2` d. none of these

A

4

B

log 4

C

log 2

D

none of these

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The correct Answer is:
To solve the problem, we need to evaluate the expression \( 0.2^{\left(\log_{\sqrt{5}} \left(\frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \ldots\right)\right)} \). ### Step 1: Identify the series The series \( \frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \ldots \) is a geometric series where: - The first term \( a = \frac{1}{4} \) - The common ratio \( r = \frac{1}{2} \) ### Step 2: Sum the geometric series The sum \( S \) of an infinite geometric series can be calculated using the formula: \[ S = \frac{a}{1 - r} \] Substituting the values we have: \[ S = \frac{\frac{1}{4}}{1 - \frac{1}{2}} = \frac{\frac{1}{4}}{\frac{1}{2}} = \frac{1}{4} \times 2 = \frac{1}{2} \] ### Step 3: Substitute the sum into the logarithm Now we substitute the sum back into the logarithm: \[ \log_{\sqrt{5}} \left(\frac{1}{2}\right) \] ### Step 4: Change of base for the logarithm Using the change of base formula for logarithms: \[ \log_{\sqrt{5}} \left(\frac{1}{2}\right) = \frac{\log \left(\frac{1}{2}\right)}{\log \left(\sqrt{5}\right)} = \frac{\log \left(\frac{1}{2}\right)}{\frac{1}{2} \log (5)} = \frac{2 \log \left(\frac{1}{2}\right)}{\log (5)} \] ### Step 5: Simplify \( \log \left(\frac{1}{2}\right) \) We know that: \[ \log \left(\frac{1}{2}\right) = -\log(2) \] Thus, \[ \log_{\sqrt{5}} \left(\frac{1}{2}\right) = \frac{2 \cdot (-\log(2))}{\log(5)} = -\frac{2 \log(2)}{\log(5)} \] ### Step 6: Substitute back into the expression Now we substitute this back into the original expression: \[ 0.2^{\left(-\frac{2 \log(2)}{\log(5)}\right)} \] Since \( 0.2 = \frac{1}{5} \), we can rewrite it as: \[ \left(\frac{1}{5}\right)^{\left(-\frac{2 \log(2)}{\log(5)}\right)} = 5^{\left(\frac{2 \log(2)}{\log(5)}\right)} \] ### Step 7: Use properties of logarithms Using the property \( a^{\log_b(c)} = c^{\log_b(a)} \), we can rewrite: \[ 5^{\left(\frac{2 \log(2)}{\log(5)}\right)} = 2^{\left(2\right)} = 4 \] ### Final Answer Thus, the value of \( 0.2^{\left(\log_{\sqrt{5}} \left(\frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \ldots\right)\right)} \) is: \[ \boxed{4} \]

To solve the problem, we need to evaluate the expression \( 0.2^{\left(\log_{\sqrt{5}} \left(\frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \ldots\right)\right)} \). ### Step 1: Identify the series The series \( \frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \ldots \) is a geometric series where: - The first term \( a = \frac{1}{4} \) - The common ratio \( r = \frac{1}{2} \) ### Step 2: Sum the geometric series ...
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