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If Hn=1+1/2+...+1/ndot , then the value ...

If `H_n=1+1/2+...+1/ndot` , then the value of `S_n=1+3/2+5/3+...+(99)/(50)` is a. `H_(50)+50` b. `100-H_(50)` c. `49+H_(50)` d. `H_(50)+100`

A

`H_50+50`

B

`100-H_50`

C

`49+H_50`

D

`H_50+ 100`

Text Solution

Verified by Experts

The correct Answer is:
B
`S_(n)=1+3/2+5/3+..+99/50`
`=(2-1)+(2-1/2)+(2-1/3)+..+(2-1/50)`
`=100-H_(50)`
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