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The first term of an arithmetic progress...

The first term of an arithmetic progression is `1` and the sum of the first nine terms equal to `369`. The first and the ninth term of a geometric progression coincide with the first and the ninth term of the arithmetic progression. Find the seventh term of the geometric progression.

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To solve the problem step by step, we will follow the information provided about the arithmetic progression (AP) and geometric progression (GP). ### Step 1: Identify the first term and the sum of the first nine terms of the AP. - The first term \( A \) of the AP is given as \( 1 \). - The sum of the first nine terms \( S_9 \) is given as \( 369 \). ### Step 2: Use the formula for the sum of the first \( n \) terms of an AP. The formula for the sum of the first \( n \) terms of an AP is: \[ S_n = \frac{n}{2} \times (2A + (n-1)D) \] For our case, \( n = 9 \), \( A = 1 \), and \( S_9 = 369 \): \[ 369 = \frac{9}{2} \times (2 \times 1 + (9-1)D) \] ### Step 3: Simplify the equation. Multiplying both sides by \( 2 \) to eliminate the fraction: \[ 738 = 9 \times (2 + 8D) \] Dividing both sides by \( 9 \): \[ 82 = 2 + 8D \] ### Step 4: Solve for \( D \). Subtract \( 2 \) from both sides: \[ 80 = 8D \] Dividing by \( 8 \): \[ D = 10 \] ### Step 5: Find the ninth term of the AP. The ninth term \( T_9 \) of the AP can be calculated using the formula: \[ T_n = A + (n-1)D \] For \( n = 9 \): \[ T_9 = 1 + (9-1) \times 10 = 1 + 80 = 81 \] ### Step 6: Relate the first and ninth terms of the GP to the AP. The first term of the GP \( G_1 \) is \( 1 \) (same as the first term of the AP). The ninth term of the GP \( G_9 \) is given by: \[ G_9 = G_1 \times R^8 = 1 \times R^8 \] Since \( G_9 \) also equals the ninth term of the AP, we have: \[ R^8 = 81 \] ### Step 7: Solve for \( R \). Taking the eighth root of both sides: \[ R = 81^{1/8} = 3^{4/8} = 3^{1/2} = \sqrt{3} \] ### Step 8: Find the seventh term of the GP. The seventh term \( G_7 \) of the GP is given by: \[ G_7 = G_1 \times R^6 = 1 \times (\sqrt{3})^6 = 3^3 = 27 \] ### Final Answer: The seventh term of the geometric progression is \( 27 \). ---

To solve the problem step by step, we will follow the information provided about the arithmetic progression (AP) and geometric progression (GP). ### Step 1: Identify the first term and the sum of the first nine terms of the AP. - The first term \( A \) of the AP is given as \( 1 \). - The sum of the first nine terms \( S_9 \) is given as \( 369 \). ### Step 2: Use the formula for the sum of the first \( n \) terms of an AP. The formula for the sum of the first \( n \) terms of an AP is: ...
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CENGAGE ENGLISH-PROGRESSION AND SERIES-EXERCIESE ( NUMERICAL VALUE TYPE )
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