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If the surm of the first ten terms of th...

If the surm of the first ten terms of the series,`(1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+........`, is `16/5m` ,then m is equal to

A

101

B

100

C

99

D

102

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The correct Answer is:
To find the value of \( m \) in the given series, we need to first analyze the series and find the sum of the first ten terms. The series is: \[ (1 \frac{3}{5})^2 + (2 \frac{2}{5})^2 + (3 \frac{1}{5})^2 + 4^2 + (4 \frac{4}{5})^2 + \ldots \] ### Step 1: Convert Mixed Numbers to Improper Fractions First, we convert the mixed numbers to improper fractions: - \( 1 \frac{3}{5} = \frac{8}{5} \) - \( 2 \frac{2}{5} = \frac{12}{5} \) - \( 3 \frac{1}{5} = \frac{16}{5} \) - \( 4 = \frac{20}{5} \) - \( 4 \frac{4}{5} = \frac{24}{5} \) ### Step 2: Identify the General Term The general term of the series can be observed as: \[ \left( \frac{4n + 4}{5} \right)^2 \] Where \( n \) is the term number starting from 1. ### Step 3: Write the Sum of the First 10 Terms The sum of the first 10 terms can be expressed as: \[ S_{10} = \sum_{n=1}^{10} \left( \frac{4n + 4}{5} \right)^2 \] This simplifies to: \[ S_{10} = \frac{1}{25} \sum_{n=1}^{10} (4n + 4)^2 \] ### Step 4: Expand the Expression Now we expand \( (4n + 4)^2 \): \[ (4n + 4)^2 = 16n^2 + 32n + 16 \] ### Step 5: Sum the Series Now we can write the sum: \[ S_{10} = \frac{1}{25} \sum_{n=1}^{10} (16n^2 + 32n + 16) \] This can be separated into three sums: \[ S_{10} = \frac{1}{25} \left( 16 \sum_{n=1}^{10} n^2 + 32 \sum_{n=1}^{10} n + 16 \sum_{n=1}^{10} 1 \right) \] ### Step 6: Use Known Formulas for Sums We use the formulas for the sums: - \( \sum_{n=1}^{k} n^2 = \frac{k(k+1)(2k+1)}{6} \) - \( \sum_{n=1}^{k} n = \frac{k(k+1)}{2} \) - \( \sum_{n=1}^{k} 1 = k \) For \( k = 10 \): - \( \sum_{n=1}^{10} n^2 = \frac{10 \cdot 11 \cdot 21}{6} = 385 \) - \( \sum_{n=1}^{10} n = \frac{10 \cdot 11}{2} = 55 \) - \( \sum_{n=1}^{10} 1 = 10 \) ### Step 7: Substitute Back into the Equation Now substituting these values back into the equation for \( S_{10} \): \[ S_{10} = \frac{1}{25} \left( 16 \cdot 385 + 32 \cdot 55 + 16 \cdot 10 \right) \] Calculating each term: - \( 16 \cdot 385 = 6160 \) - \( 32 \cdot 55 = 1760 \) - \( 16 \cdot 10 = 160 \) Thus, \[ S_{10} = \frac{1}{25} (6160 + 1760 + 160) = \frac{1}{25} \cdot 8090 = \frac{8090}{25} \] ### Step 8: Set Equal to Given Expression We are given that: \[ S_{10} = \frac{16}{5} m \] Setting the two expressions equal: \[ \frac{8090}{25} = \frac{16}{5} m \] ### Step 9: Solve for \( m \) Cross-multiplying gives: \[ 8090 \cdot 5 = 16 \cdot 25 m \] \[ 40450 = 400 m \] Thus, \[ m = \frac{40450}{400} = 101.125 \] ### Final Step: Conclusion Since \( m \) must be an integer, we round it to \( 101 \). So, the value of \( m \) is: \[ \boxed{101} \]

To find the value of \( m \) in the given series, we need to first analyze the series and find the sum of the first ten terms. The series is: \[ (1 \frac{3}{5})^2 + (2 \frac{2}{5})^2 + (3 \frac{1}{5})^2 + 4^2 + (4 \frac{4}{5})^2 + \ldots \] ### Step 1: Convert Mixed Numbers to Improper Fractions First, we convert the mixed numbers to improper fractions: ...
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