If `y_1` and `y_2` are two solutions to the differential equation `(dy)/(dx)+P(x)y=Q(x)` . Then prove that `y=y_1+c(y_1-y_2)` is the general solution to the equation where `c` is any constant.

Explanation

To prove that \( y = y_1 + c(y_1 - y_2) \) is the general solution to the differential equation

\[ \frac{dy}{dx} + P(x)y = Q(x) \]

where \( y_1 \) and \( y_2 \) are two solutions of the differential equation, we will follow these steps:

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