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Solve the equation ydx+(x-y^2)dy=0...

Solve the equation `ydx+(x-y^2)dy=0`

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To solve the differential equation \( y \, dx + (x - y^2) \, dy = 0 \), we can follow these steps: ### Step 1: Rearranging the Equation We start by rearranging the equation to isolate \( dx \) and \( dy \): \[ y \, dx = y^2 \, dy - x \, dy \] This can be rewritten as: \[ dx = \frac{y^2 - x}{y} \, dy \] ### Step 2: Writing in the Form of a Linear Differential Equation We can express \( \frac{dx}{dy} \) as: \[ \frac{dx}{dy} = \frac{y^2 - x}{y} \] This can be rearranged to: \[ \frac{dx}{dy} + \frac{x}{y} = y \] This is now in the standard form of a linear differential equation, \( \frac{dx}{dy} + P(y)x = Q(y) \), where \( P(y) = \frac{1}{y} \) and \( Q(y) = y \). ### Step 3: Finding the Integrating Factor To solve this linear differential equation, we need to find the integrating factor \( \mu(y) \): \[ \mu(y) = e^{\int P(y) \, dy} = e^{\int \frac{1}{y} \, dy} = e^{\ln |y|} = |y| = y \quad (\text{assuming } y > 0) \] ### Step 4: Multiplying the Equation by the Integrating Factor Now we multiply the entire equation by the integrating factor \( y \): \[ y \frac{dx}{dy} + x = y^2 \] ### Step 5: Recognizing the Left Side as a Derivative The left-hand side can be recognized as the derivative of a product: \[ \frac{d}{dy}(xy) = y^2 \] ### Step 6: Integrating Both Sides Now we integrate both sides with respect to \( y \): \[ \int \frac{d}{dy}(xy) \, dy = \int y^2 \, dy \] This gives us: \[ xy = \frac{y^3}{3} + C \] where \( C \) is the constant of integration. ### Step 7: Solving for \( x \) Finally, we can solve for \( x \): \[ x = \frac{y^2}{3} + \frac{C}{y} \] ### Final Solution The general solution of the differential equation is: \[ x = \frac{y^2}{3} + \frac{C}{y} \] ---

To solve the differential equation \( y \, dx + (x - y^2) \, dy = 0 \), we can follow these steps: ### Step 1: Rearranging the Equation We start by rearranging the equation to isolate \( dx \) and \( dy \): \[ y \, dx = y^2 \, dy - x \, dy \] This can be rewritten as: ...
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