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The graph of the function y=f(x) passing...

The graph of the function `y=f(x)` passing through the point (0,1) and satisfying the differential equation `(dy)/(dx)+ycosx=cosx` is such that (a) it is a constant function. (b) it is periodic (c) it is neither an even nor an odd function. (d) it is continuous and differentiable for all `( e ) (f) xdot( g )` (h)

A

It is constant function

B

It is periodic

C

it is neither an even nor an odd function.

D

it is continuous and differentiable for all x

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

`(dy)/(dx)+ycosx=cosx` (linear)
I.F. =`e^(intcosxdx)=e^(sinx)`
Thus, solution is `ye^(sinx)=inte^(sinx)cosxdx=e^(sinx)+c`
When `x=0, y=1`, then c=0
Thus, y=1. Hence, option (1), (2), (4) are true.
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