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Find the curves for which the length of ...

Find the curves for which the length of normal is equal to the radius vector.

A

circles

B

rectangular hyperbola

C

ellipses

D

straight lines

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To solve the problem of finding the curves for which the length of the normal is equal to the radius vector, we can follow these steps: ### Step 1: Understand the Definitions The length of the normal at a point on a curve is given by the formula: \[ L_n = y \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \] The radius vector (the distance from the origin to the point \((x, y)\)) is given by: \[ L_r = \sqrt{x^2 + y^2} \] ### Step 2: Set Up the Equation According to the problem, we need to set the length of the normal equal to the radius vector: \[ y \sqrt{1 + \left(\frac{dy}{dx}\right)^2} = \sqrt{x^2 + y^2} \] ### Step 3: Square Both Sides To eliminate the square roots, we square both sides of the equation: \[ y^2 (1 + \left(\frac{dy}{dx}\right)^2) = x^2 + y^2 \] ### Step 4: Simplify the Equation Expanding the left side gives us: \[ y^2 + y^2 \left(\frac{dy}{dx}\right)^2 = x^2 + y^2 \] Subtracting \(y^2\) from both sides results in: \[ y^2 \left(\frac{dy}{dx}\right)^2 = x^2 \] ### Step 5: Rearranging the Equation We can rearrange this to isolate \(\frac{dy}{dx}\): \[ \left(\frac{dy}{dx}\right)^2 = \frac{x^2}{y^2} \] Taking the square root of both sides gives us two cases: \[ \frac{dy}{dx} = \frac{x}{y} \quad \text{or} \quad \frac{dy}{dx} = -\frac{x}{y} \] ### Step 6: Solve the Differential Equations 1. **For \(\frac{dy}{dx} = \frac{x}{y}\)**: - This can be rewritten as: \[ y \, dy = x \, dx \] - Integrating both sides: \[ \frac{y^2}{2} = \frac{x^2}{2} + C_1 \implies y^2 - x^2 = C_1 \] 2. **For \(\frac{dy}{dx} = -\frac{x}{y}\)**: - This can be rewritten as: \[ y \, dy = -x \, dx \] - Integrating both sides: \[ \frac{y^2}{2} = -\frac{x^2}{2} + C_2 \implies y^2 + x^2 = C_2 \] ### Step 7: Identify the Curves The first equation \(y^2 - x^2 = C_1\) represents a rectangular hyperbola, while the second equation \(y^2 + x^2 = C_2\) represents a circle. ### Final Result Thus, the curves for which the length of the normal is equal to the radius vector are: 1. Rectangular hyperbolas: \(y^2 - x^2 = C_1\) 2. Circles: \(x^2 + y^2 = C_2\) ---

To solve the problem of finding the curves for which the length of the normal is equal to the radius vector, we can follow these steps: ### Step 1: Understand the Definitions The length of the normal at a point on a curve is given by the formula: \[ L_n = y \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \] The radius vector (the distance from the origin to the point \((x, y)\)) is given by: ...
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