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Suppose a solutions of the differential equation `(xy^3 + x^2y^7) dy/dx =1 ` satisfies the initial conditions `y(1/4)=1.` Then the value of `dy/dx` when `y = -1` is

A

`-(3)/(20)`

B

`-(20)/(3)`

C

`-(5)/(16)`

D

`-(16)/(5)`

Text Solution

Verified by Experts

The correct Answer is:
D

`(dx)/(dy)=xy^(3)+x^(2)y^(7)`
`rArr" "(1)/(x^(2))(dx)/(dy)-(1)/(x)y^(3)=y^(7)`
`rArr" "(d(-1//x))/(dy)-(1)/(x)(y^(3))=y^(7)`
`I.F.=e^(y^(4)//4)`
Solution is `(-e^(y^(4)//4))/(x)=y^(4)e^(y^(4)//4)-4e^(y^(4)//4)-e^(1//4)`
when `y = -1, x = (1)/(4)`
`therefore" "(dy)/(dx) = -(16)/(5)`
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