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Let fa n dg be differentiable on R and s...

Let `fa n dg` be differentiable on `R` and suppose `f(0)=g(0)a n df^(prime)(x)lt=g^(prime)(x)` for all `xgeq0.` Then show that `f(x)lt=g(x)` for all `xgeq0.`

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To solve the problem, we need to show that if \( f(0) = g(0) \) and \( f'(x) \leq g'(x) \) for all \( x \geq 0 \), then \( f(x) \leq g(x) \) for all \( x \geq 0 \). ### Step-by-Step Solution: 1. **Define a new function**: Let \( p(x) = f(x) - g(x) \). This function represents the difference between \( f \) and \( g \). 2. **Differentiate the new function**: ...
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