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Let f(x)=sin^3x+lambda sin^2x , -pi/2 < ...

Let `f(x)=sin^3x+lambda sin^2x , -pi/2 < x < pi/2` Find the intervals in which `lambda` should lie in order that `f(x)` has exactly one minimum and exactly one maximum.

Text Solution

Verified by Experts

We have
`f(x)=2(x-1)(x-2)3+3(-1)2(x-2)^(2)2`
`=(x-1)(x-2)^(2)(5x-7)`
Sign schem of f(x) is as shown in the following figure

Clearly f(x) has point of maxima at x=1 and point of minima t `x=7//5`
Also sign of derivative is not changing at x=2 so it is not a point of extrema.
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