Displacement `s` of a particle at time `t` is expressed as `s=1/2t^3-6tdot` Find the acceleration at the time when the velocity vanishes (i.e., velocity tends to zero).

Displacement s of a particle at time t is expressed as s=1/2t^3-6t . Find the acceleration at the time when the velocity vanishes (i.e., velocity tends to zero).

The distance s of a particle in time t is given by s=t^3-6t^2-4t-8 . Its acceleration vanishes at t=

If the displacement of a particle is givne by s=((1)/(2)t^(2)+4sqrtt)m . Find the velocity and acceleration at t = 4 seconds.

A particle moves along the x-axis obeying the equation x=t(t-1)(t-2) , where x is in meter and t is in second a. Find the initial velocity of the particle. b. Find the initial acceleration of the particle. c. Find the time when the displacement of the particle is zero. d. Find the displacement when the velocity of the particle is zero. e. Find the acceleration of the particle when its velocity is zero.

The displacement of a particle moving along the x-axis is given by equation x=2t^(3)-21"t"^(2)+60t+6 .The possible acceleration of the particle when its velocity is zero is

The velocity of a particle is zero at time t = 2s, then

The displacement of a body at any time t after starting is given by s=15t-0.4t^2 . Find the time when the velocity of the body will be 7ms^-1 .

The displacement of a particle along the x-axis is given by x=3+8t+7t^2 . Obtain its velocity and acceleration at t=2s .

If s=4t+(1)/(t) is the equation o motion of a particle, then the acceleration when velocity vanishes, is

Velocity of a particle at time t=0 is 2 hati m/s. A constant acceleration of 2 m/s^2 acts on the particle for 2 s at an angle of 60^@ with its initial velocity. Find the magnitude of velocity and displacement of particle at the end of t=2s.