Home
Class 12
MATHS
The normal to the curve y(x-2)(x-3)=x+6 ...

The normal to the curve `y(x-2)(x-3)=x+6` at the point where the curve intersects the `y-axis ,` passes through the point : (1)`(1/2,-1/3)` (2) `(1/2,1/3)` (3) `(-1/2,-1/2)` (4) `(1/2,1/2)`

A

`((1)/(2),(1)/(3))`

B

`(-(1)/(2),-(1)/(2))`

C

`((1)/(2),(1)/(2))`

D

`((1)/(2),(1)/(3))`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise ILLUSTRATION|62 Videos
  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise SOLVED EXAMPLES|15 Videos
  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise NUMERICAL VALUE TYPE|19 Videos
  • 3D COORDINATION SYSTEM

    CENGAGE ENGLISH|Exercise DPP 3.1|11 Videos
  • APPLICATION OF INTEGRALS

    CENGAGE ENGLISH|Exercise All Questions|142 Videos

Similar Questions

Explore conceptually related problems

The normal to the curve x^(2)+2xy-3y^(2)=0, at (1,1)

Find the equation of the tangent to the curve y=(x^3-1)(x-2) at the points where the curve cuts the x-axis.

Find the equation of the tangent to the curve y=(x^3-1)(x-2) at the points where the curve cuts the x-axis.

The equation of the normal to the curve y=e^(-2|x|) at the point where the curve cuts the line x = 1//2 is

The equation of the normal to the curve y= e^(-2|x|) at the point where the curve cuts the line x=-(1)/(2), is

Equation of the normal to the curve y=-sqrt(x)+2 at the point (1,1)

Find the equation of the normal to the curve x^2=4y which passes through the point (1, 2).

Find the equation of the normal to curve x^2=4y which passes through the point (1, 2).

Find the equation of the normal to curve x^2=4y which passes through the point (1, 2).

Find the equation of the normal to the curve 2y=x^2 , which passes through the point (2,1).