A bag contains 20 tickets, numbered from 1 to 20. Two tickets are drawn without replacement. What is the probability that the first ticket has an even number and the second an odd number.

Explanation

There are total `20` tickets numbered from `1` to `20`.

So, `10` tickets has even number and `10` tickets have odd numbers.

Now, probability of drawing a ticket that has even number ` = 10/20 = 1/2`

Now, there are total `19` tickets and `10` odd tickets are available.

`:.` Probability of drawing a ticket that has odd number `= 10/19`

`:.` Required probability ` = 1/2**10/19 = 5/19`