Find `(dy)/(dx),w h e n` `x=e^(theta)(theta+1/theta)a n dy=e^(-theta)(theta-1/theta)`

Explanation

To find \(\frac{dy}{dx}\) given the equations:

\[ x = e^{\theta} \left( \theta + \frac{1}{\theta} \right) \]
\[ y = e^{-\theta} \left( \theta - \frac{1}{\theta} \right) \]
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