The plane `x-2y+3z=0` is rotated through a right angle about the line of intersection with the plane `2x+3y-4z-5=0,` find the equation of the plane in its new position.

The plane 4x+7y+4z+81=0 is rotated through a right angle about its line of intersection with the plane 5x+3y+10 z=25. The equation of the plane in its new position is a. x-4y+6z=106 b. x-8y+13 z=103 c. x-4y+6z=110 d. x-8y+13 z=105

The plane 4x+7y+4z+81=0 is rotated through a right angle about its line of intersection with the plane 5x+3y+10 z=25. The equation of the plane in its new position is x-4y+6z=k where k is

The plane x-y-z=4 is rotated through an angle 90^(@) about its line of intersection with the plane x+y+2z=4 . Then the equation of the plane in its new position is

The plane l x+m y=0 is rotated through an angle alpha about its line of intersection with the plane z=0 . Prove that the equation of the plane in its new position is l x+m ypm(sqrt(l^2+m^2)tanalpha)z=0.

The plane a x+b y=0 is rotated through an angle alpha about its line of intersection with the plane z=0. Show that he equation to the plane in the new position is ax+by±z sqrt(a ^ 2 +b^ 2) ​ tanα=0

The plane x- y - z = 2 is rotated through an angle pi/2 about its line of intersection with the plane x + 2y + z = 2 . Find its equation in the new position.

The plane ax+by=0 is rotated through an angle alpha about its line of intersection with the plane z=0 . Show that the equation to the plane in new position is ax+bypmzsqrt(a^2+b^2)tanalpha=0 .

The plane denoted by P_1 : 4x+7y+4z+81=0 is rotated through a right angle about its line of intersection with plane P_2 : 5x+3y+10z=25 . If the plane in its new position be denoted by P, and the distance of this plane from the origin is d, then the value of [(k)/(2)] (where[.] represents greatest integer less than or equal to k) is....

The plane denoted by pi_(1) : 4x+7y+4z+81=0 is rotated through a right angle about its line of intersection with the plane pi_(2) : 5x+3y+ 10 z = 25 . If the plane in its new position is denoted by pi , and the distance of this plane from the origin is sqrtk , where k in N , then k=

The plane ax + by = 0 is rotated about its line of intersection with the plane z = 0 through an angle alpha . Prove that the equation of the plane in its new position is ax + by +- (sqrt(a^2 + b^2) tan alpha)z = 0