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If A=[1 1 1 0 1 1 0 0 1] , then use the ...

If `A=[1 1 1 0 1 1 0 0 1]` , then use the principle of mathematical induction to show that `A^n=[1 n n(n+1)//2 0 1 n 0 0 1]` for every positive integer `n` .

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