Show that `f(x)=|x-3|` is continuous but not differentiable at `x=3` .

Explanation

To show that the function \( f(x) = |x - 3| \) is continuous but not differentiable at \( x = 3 \), we will follow these steps:

### Step 1: Define the function piecewise
The absolute value function can be expressed in a piecewise manner:
\[
f(x) =
\begin{cases}
x - 3 & \text{if } x \geq 3 \\
...