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The temperature T of a cooling object dr...

The temperature T of a cooling object drops at a rate proportional to the difference `T - S` where S is constant temperature of surrounding medium. If initially `T = 150^@C`; find the temperature of the cooling object at any time t.

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Newton's law of cooling states that the rate of change of the temperature T of an object is proportional to the difference between T and the (constant) temperature tau of the surrounding medium, we can write it as (dT)/(dt) = -k(T - tau) k gt 0 constant An cup of coffee is served at 185^(@)F in a room where the temperature is 65^(@)F . 2 minutes later the temperature of the coffee has dropped to 155^(@)F . log_(e)3 = 1.09872, log_(e).(3)/(4) = 0.2877 Temperature of coffee at time t is given by

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